Math, asked by numansayyed9822, 2 months ago

104 sweets were distributed to Class A and Class B in the ratio 6:7

how many sweet did class a get?​

Answers

Answered by Namjoonie7
11

Step-by-step explanation:

There are two ways to solve this answer

Method 1(for class 7 and above)

Let the number of sweets each class geets be 6y and 7y

ATQ

6y+7y=104

13y=104

y=104/13

y=8

sweets class a got=6y=6×8=48

sweets class b got =7y=7×8=56

Method 2(for class 6)

Sum of ratios =6+7=13

Sweets class A got=6/13×104 =57

Sweets class b got= 7/13×104 =56

Answered by shakeelkhan06655
0

Answer:

so we can talk about it tomorrow

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