104 sweets were distributed to Class A and Class B in the ratio 6:7
how many sweet did class a get?
Answers
Answered by
11
Step-by-step explanation:
There are two ways to solve this answer
Method 1(for class 7 and above)
Let the number of sweets each class geets be 6y and 7y
ATQ
6y+7y=104
13y=104
y=104/13
y=8
sweets class a got=6y=6×8=48
sweets class b got =7y=7×8=56
Method 2(for class 6)
Sum of ratios =6+7=13
Sweets class A got=6/13×104 =57
Sweets class b got= 7/13×104 =56
Answered by
0
Answer:
so we can talk about it tomorrow
Similar questions