Question

104abc(4a-16)(7b-21)÷169(a-4)(b-3)​

Answer 1

answer is 224abc/13

your question is -> [104abc(4a - 16)(7b - 21)]/[169(a - 4)(b - 3)]

first resolving numerator into simpler form

104abc(4a - 16)(7b - 21) = 104abc(4a - 4 × 4)(7b - 7 × 3)

= 104abc × 4(a - 4) × 7(b - 3)

= 104 × 28 abc (a - 4)(b - 3)

now, putting simpler from of numerator in expression.

[104 × 28 abc (a - 4)(b - 3)]/[169(a - 3)(b - 3)]

= 104 × 28 abc/169

= (13 × 8 × 28 abc)/(13 × 13)

= 224abc/13

hence answer is 224abc/13

also read similar questions : If a/b=2/3 then find the values of 7b-4a/7b+4a.

https://brainly.in/question/4594619

If 3a+7b/3a-7b=4/3 then find the value of the ratio 3a²-7b²/3a²+7b²

https://brainly.in/question/11760513

Answer 2

The simplified expression to the given expression is $\frac{224abc}{13}$

Therefore $\frac{104abc(4a-16)(7b-21)}{169(a-4)(b-3)}=\frac{224abc}{13}$

Step-by-step explanation:

Given expression is $\frac{104abc(4a-16)(7b-21)}{169(a-4)(b-3)}$

To simplify the given expression as below :

• $\frac{104abc(4a-16)(7b-21)}{169(a-4)(b-3)}$
• $=\frac{8abc(4a-16)(7b-21)}{13(a-4)(b-3)}$
• $=\frac{8abc(4(a-4))(7(b-3))}{13(a-4)(b-3)}$
• $=\frac{8abc(4)(7)}{13}$
• $=\frac{224abc}{13}$

• $\frac{104abc(4a-16)(7b-21)}{169(a-4)(b-3)}=\frac{224abc}{13}$

Therefore the simplified expression to the given expression is $\frac{224abc}{13}$

Therefore $\frac{104abc(4a-16)(7b-21)}{169(a-4)(b-3)}=\frac{224abc}{13}$