104x105 using identities
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Answered by
6
=104×105
=(100+4)(100+5)
[USING (x+a)(x+b)=x²+(a+b)x+ab]
=(100)²+(4+5)100+(4×5)
=10000+(9)100+20
=10000+900+20
=10920
=(100+4)(100+5)
[USING (x+a)(x+b)=x²+(a+b)x+ab]
=(100)²+(4+5)100+(4×5)
=10000+(9)100+20
=10000+900+20
=10920
Answered by
2
104*105
identity =x²+(a+b)x+ab
(100+4)(100+5)
(100)²+ (4+5)100 +(4)(5)
10000+900+20
10920
identity =x²+(a+b)x+ab
(100+4)(100+5)
(100)²+ (4+5)100 +(4)(5)
10000+900+20
10920
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