(105)^3 write this cube in expanded form
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Answered by
0
Answer:
Solution: (i) (2x + 1)³ ...
(a + b)³ = a³+ b³+ 3ab(a + b) (2x + 1)³ ...
= 8x³ + 1 + 12x² + 6x. (ii) (2a – 3b)³ ...
(a – b)³ = a³–b³ – 3ab(a – b) (2a – 3b)³ = (2a)³– (3b)³ – (3×2a×3b)(2a – 3b) ...
= 8a³–27b³–36a²b + 54ab² (iii) [3x/2 + 1]³ ...
(a + b)³ = a³+ b³+ 3ab(a + b) ...
= (27/8)x³ + (27/4) x² + 9/2 x + 1. ...
(a - b)³=a³-b³-3ab(a-b)
Answered by
1
Answer:
1157625
Step-by-step explanation:
Using identity : (a+b)³=a³+b³+3ab(a+b)
=> (100)³+(5)³+3×(100)×(5)×(100+5)
=> 1000000+125+1500×105
=> 1000125+157500
=> 1157625
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