Question

105
. Find the value of x when y = 5, if x varies
directly as 4y - 1 and x = 14 when y = 2.
(b) 35 (C) 10 (d) 28
(a) 38​

Answer 1

Answer:

Let z = 4y-1

When x = 14, y = 2, z = (4*2) – 1 = 7

Now, x varies directly as z = 4y-1

When y = 5, z = (4*5) – 1 = 19

x 14 7

y – 19

Therefore, x = (14*19)/7 = 38

Step-by-step explanation: