105 g water is saturated with ammonia gas to form a solution of density 1.0g/ml and containing 30 %ammonia, by mass. what is the volume of solution formed?
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Given -
volume of water = 105 mL
density of solution = 0.9 g/mL
Calculation -
Since ammonia dissolved in water is 30% by weight, then using mass % formula, we can calculate the amount of ammonia in water.
mass % = mass of ammoniamass of solution×100
30 = mass of ammoniamass of ammonia + mass of water×100
At 4oC, density of water = 0.999 g/mL
since density = mass /volume
0.999 = mass/ 105
mass of water = 104.895 g
now, let mass of ammonia be x.
30/100 = xx+ 104.895
30x + 3146.85 = 100x
70x = 3146.85
x = 44.955 g
Thus, ammonia dissolved in 105 mL water is 44.955 g
Therefore, total mass of solution = mass of ammonia + mass of water
Mass of solution = 44.955 + 104.895
Mass of solution = 149.85 g
So,density of solution = mass of solution / volume of solution
0.9 g/mL = 149.85 g / Volume of solution
Volume of solution = 149.85/ 0.9
Volume of solution = 166.5 mL
volume of water = 105 mL
density of solution = 0.9 g/mL
Calculation -
Since ammonia dissolved in water is 30% by weight, then using mass % formula, we can calculate the amount of ammonia in water.
mass % = mass of ammoniamass of solution×100
30 = mass of ammoniamass of ammonia + mass of water×100
At 4oC, density of water = 0.999 g/mL
since density = mass /volume
0.999 = mass/ 105
mass of water = 104.895 g
now, let mass of ammonia be x.
30/100 = xx+ 104.895
30x + 3146.85 = 100x
70x = 3146.85
x = 44.955 g
Thus, ammonia dissolved in 105 mL water is 44.955 g
Therefore, total mass of solution = mass of ammonia + mass of water
Mass of solution = 44.955 + 104.895
Mass of solution = 149.85 g
So,density of solution = mass of solution / volume of solution
0.9 g/mL = 149.85 g / Volume of solution
Volume of solution = 149.85/ 0.9
Volume of solution = 166.5 mL
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