Question

105 goats , 140 donkeys and 175 cows have to be taken across a river. There is only one boatwhich will have to make many trips in order to do so. The lazy boatman has his own conditions fortransporting them. He insists that he will take the same number of animals in every trip and they have tobe of the same kind. He will naturally like to take the largest possible number each time. Can you tellhow many animals went in each trip?

Answer 1

The highest number by which 105,140 and 175 are divisible is 35 (GCF). There are 420 animals so it must be divisible by 35. So number of trips fulfilling the above conditions is: 12. 

Answer 2

Answer:

35 Animals

Step-by-step explanation:

Given:

Number of goats = 105

Number of donkeys = 140

Number of cows = 175

To find:

The largest number of animals in one trip the HCF (105, 140 and 175) has to be calculated.

Solution:

Now, first consider the numbers 105 and 140 and apply division lemma

140 = 105 x 1 + 35

105 = 35 x 3 + 0

Thus, the HCF (105 and 140) = 35

Now, consider 35 and the third number 175 and Apply Euclid’s division lemma

175 = 35 x 5 +0

Hence, the HCF (105, 140, 175) = 35.

=Therefore, it can be said that 35 animals went on each trip.

$\rm \purple{Thanks}$