Question

105 goats, 140 donkeys and 175 cows have to be taken across a river. There is only one
boat which will have to make many trips in order to do so. The lazy boatman has hi
own conditions for transporting them. He insists that he will take the same number
animals in every trip and they have to be of the same kind. He will naturally like to take
the largest possible number each time. Can you tell how many animals went in each trip?​

Answer 1

Answer:

Number of goats = 105

Number of donkeys = 140

Number of cows = 175.

Therefore, the largest number of animals in 1 trip = H.C.F. of 105, 140 and 175.

First we consider 105 and 140.

By applying Euclid’s division lemma

Therefore, H.C.F. of 105 and 140 = 35

Now, we consider 35 and 175.

By applying Euclid’s division lemma

Therefore, H.C.F. of 105, 140 and 175 = 35

Hence, the number of animals went