Question

105 goats, 140 donkeys and 175 cows have to be taken across a river. There is only one boat
which will have to make many trips in order to do so. The lazy boatman has his own
conditions for transporting them. He insists that he will take the same number of animals in
every trip and they have to be of the same kind. He will naturally like to take the largest
possible number each time. Can you tell how many animals went in each trip?​

Answer 1

Answer:

so you need find the hcf

105=3*5*7

140=2*2*5*7

175=5*5*7

so the hcf is 35

so at a time he can transport 35 of same kind

Answer 2

Given:

Number of goats = 105

Number of donkeys = 140

Number of cows = 175

To find:

The largest number of animals in one trip the HCF (105, 140 and 175) has to be calculated.

Solution:

Now, first consider the numbers 105 and 140 and apply division lemma

140 = 105 x 1 + 35

105 = 35 x 3 + 0

Thus, the HCF (105 and 140) = 35

Now, consider 35 and the third number 175 and Apply Euclid’s division lemma

175 = 35 x 5 +0

Hence, the HCF (105, 140, 175) = 35.

=Therefore, it can be said that 35 animals went on each trip.