Question

105 goats, 140 donkeys and 175 cows have to be taken across a river. there is only one boat which will have to make many trips in order to do so. the lazy boatman has his own conditions for transporting them. he insists that he will take the same number of animals in every trip and they have to be of the same kind. he will naturally like to take the largest possible number each time. can you tell how many animals went in each trip

Answer 1

Take lcm of 105,140,175 and your answer is here

Answer 2

Given:

Number of goats = 105

Number of donkeys = 140

Number of cows = 175

To find:

The largest number of animals in one trip the HCF (105, 140 and 175) has to be calculated.

Solution:

Now, first consider the numbers 105 and 140 and apply division lemma

140 = 105 x 1 + 35

105 = 35 x 3 + 0

Thus, the HCF (105 and 140) = 35

Now, consider 35 and the third number 175 and Apply Euclid’s division lemma

175 = 35 x 5 +0

Hence, the HCF (105, 140, 175) = 35.

=Therefore, it can be said that 35 animals went on each trip.