Question

105. How much amount of CuSO4.5H2O is required for
liberation of 2.54 g of I, when titrated with KI?
(a) 2.5 g
(b) 4.99 g
(c) 2.4 g
(d) 1,2 g (AIIMS)​

Answer 1

Answer:

4.99 gm

Explanation:

Equivalent of I2 = 2.54/254 ×2 = 0.02 (since 2I- changes to I2 + 2e)

Equivalent of I2 = CuSO4.5H2O = 0.02

weight of CuSO4.5H2O = 0.02 × 249.6/1 (since valency of Cu change from +2 to +1)

= 4.99 gm

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