Question

(105)ki cube by using indetities​

Answer 1

105³

105 can be written as (100 + 5)

So, 105³ can be written as,

(100 + 5)³

we know that (a+b)³ = a³+b³+3ab(a+b)

(100 + 5)³ = 1000000 + 125 + 3*100*5 (100+5)

= 1000125 + 1500(105)

=1157625

Hope that answered your question.

Answer 2

Answer 1157625

Step-by-step explanation:

(105)^3

(a+b)^3=a^3 + 3a^2 b + 3ab^2+b^3

(100+5)^3

=100^3+150000+7500+125

1157625