Question

?
105.
sin 35° tan 12°
cos 55° cot 78°
sin 18°
cos 72°
(1) 1
(2) 0
(3) 3
(4) -1​

Answer 1

Given :   Sin35°  Tan12° Sin 18° / ( Cos 55° Cot78° Cos 72°)

To Find :  Value

(1) 1

(2) 0

(3) 3

(4) -1​

Solution:

Sin35°  Tan12° Sin 18° / ( Cos 55° Cot78° Cos 72°)

Cos x = Sin(90 - x)  or Sinx = Cos(90 - x)

Tanx = Cot (90- x) or Cotx = Tan(90 - x)

Cos 55° = Sin35°

Cot78° = Tan 12°

Cos 72° = Sin 18°

Sin35°  Tan12° Sin 18° / ( Cos 55° Cot78° Cos 72°)

= Sin35°  Tan12° Sin 18° / ( Sin35°  Tan12° Sin 18° )

= 1

Sin35°  Tan12° Sin 18° / ( Cos 55° Cot78° Cos 72°) = 1

Correct value is 1

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Answer 2

Answer:

1 right answer hoga option (1)