Math, asked by lahaseatharva, 10 months ago

105 workers complete work in 140 days if they work are 35 days then and then 35 worker of them refused to work with others then how many total number of days required to complete the work

Answers

Answered by RvChaudharY50
31

||✪✪ CORRECT QUESTION ✪✪||

105 workers can complete work in 140 days .. if they work together for 35 days and then 35 worker of them refused to work with others.. Then how many total number of days required to complete the work ?

|| ✰✰ ANSWER ✰✰ ||

It is Given That , 105 workers Started The job First , and after 35 days , 35 workers Refused to work now .

So,

Days left to be done now = 140 - 35 = 105 days.

And,

workers left now = 105 - 35 = 70 workers.

________________

So, our Question is now, if 105 workers Can complete The rest of The work in 105 days. ( if no one Left ). Than in How many days 70 workers will do This work now ?

Let They complete The rest work in x days.

Than,

→ 105 * 105 = 70 * x

→ x = 157.5 days.

So, Rest work now, Completed by 70 workers in = 157.5 days.

and Before leaving 105 workers work together for = 35 days.

Hence, Total number of days required to complete the work = 157.5 + 35 = 192.5 days.

Answered by Anonymous
50

\huge{\mathfrak{Bonjour!♡}}•°⭑

Question:

105 workers complete work in 140 days if they work are 35 days then and then 35 worker of them refused to work with others then how many total number of days required to complete the work ??

Answer:

\longrightarrow{\bf{192.5\:days}}

Solution:

\longrightarrowDays left = 140 -35 = 105 days

and

\longrightarrowworkers left = 205-35 = 70 workers

let they complete the rest work in x days

105×105 = 70 x

x= 157.5 days

\longrightarrowTotal no. of days :

rest work days completed by 70 workers+ days before leaving of 105 workers

\longrightarrowRest work completed by 70 workers in 157. days

\longrightarrowdays before leaving of 105 workers

\longrightarrow{\underline{\overline{\bf{\mid{157.5+35 =192.5 days}\mid}}}}

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