Question

106,107,76,109, 187,95, 125,92, 70,139, 128,100, 88,84, 99,113, 204,141, 136,123, 90,115, 110,97, 90,107, 75,89, 118,82 Construct a continuous grouped frequency distribution for the above data with class interval as 60-80, 80-100 etc​

Answer 1

Answer:

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Step-by-step explanation:

Here , class width = 20

class mark = 70

Half of the class width =20 /2 =10

Upper limit of first class interval = 70 + 10 = 80

Lower limit of first class interval = 70 – 10 = 60

Thus, class interval becomes 60 – 80

So, frequency distribution table becomes :

(a) Number of oranges weights more than 180 g = 1 + 1 = 2

(b) Number of oranges weights less than 100 g = 3 + 10 = 13

Answer 2

The following data given the weight (in grams) of 30 oranges picked from a basket:

106 107 76 109 187 95 125 92 70

139 128 100 88 84 99 113 204 141

136 123 90 115 110 97 90 107 75

80 118 82

Construct a grouped frequency distribution table taking class width equal to 20 in such a way that the mid-value of first class in 70.

From the frequency table, find the number of oranges

(i) weighing more than 180 g.

(ii) less than 100 g.