Question

106. The work done in moving an alpha par-
ticle between two points having potential dif-
ference 25 V is-​

Answer 1

Answer:

your answer is

Explanation:

Hola User________________

Here is Your Answer..!!!

_________________________

⭐Actually welcome to the concept of the E LECTROSTATICS...

⭐Basically we know that. ..

⭐Work done = F . dr

⭐but also we know that .. electric force is given by ..

⭐F = qE ..

⭐so substituting we get as ..

⭐W = qE. dr

⭐there fore ... since ( E.dr = V = potential ..)

⭐so we get as W = qV..

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work done by alpha partical=25v

because we know that w=f.dr

1. w=qe.dr
2. therefore w=qv (v=e.dr)
3. w=2(1.6*10^19)*25
4. 50(1.6*10^19)
5. (80.10^19)
6. 8.10^18 joules.

I hope it's a helpful for you

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Answer 2

Answer:

Work done = 8×10^-18 Nm or 8×10^-18 Joule.

Explanation:

Here, F is force

q is the charge

d is distance

E is electric field

V is potential difference

Work done = qV

Work done= 3.2 × 10^-19×25 joule

Work done = 80×10^-19 joule

Work done = 8×10^-18 joule

Electric field

• Electric field is the space around the charge where another charges experiences some force due to the first charge .
• Si unit of electric field is newton/Coulomb.

Electric potential

• Energy of electrical charge measured by its power to do work .
• Si unit of electric potential is volt.