Question

107 digit number is formed by writing first 58 natural numbers next to each other. Find the remainder when number is divided by 8.

Answer 1

$\mathfrak{\huge{\blue{\underline{\underline{AnswEr :}}}}}$

1 to 9 = 9 digits

Then 10 to 58 (this is 49 two digit numbers) = 98 digits

Total 107 digits

Last digits⇒5758

The Remainder is 2

Answer 2

The remainder is 6    

Given:

107 digit number is formed by writing first 58 natural numbers next to each other.

To find:

The remainder when number is divided by 8.

Solution:

107 digit number is formed by writing first 58 natural numbers next to each other

Then the 107 digit number will be 12345......5758  

The remainder when 12345......5758 is divisible by 8 will be equal to the remainder when 5758 is divisible by 8  

⇒  divide 5758 by 8

⇒  when we divide 5758 by 8 the remainder will be equal to 6

⇒ Therefore the remainder when 12345......5758 is divisible by 8 is 6

The remainder is 6    

#SPJ2