Question

108.
108. A current of 2 amp is drawn by a filament by an
electric bulb. No. of electrons passing through a
cross section of the filament in 8 seconds would
be approximately
(1) 10
10"
(2) 10"
(4) 10
.
(3)
109​

Answer 1

Answer:

I = Q/t

Q = It

Also It = number of electrons × charge of electron

It = NE

Where N is the number of electrons

1 × 16/ 1.6 × 10^-19 it comes to 10^ 20