108÷ [35-{48 ÷ 24 + (16-19)]
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Answer:
=108÷[35-[48÷24+(16-19)]
=108÷[35-[48÷24+(-3)
=108÷[35-[48÷24-3]
=108÷[35-[2-3]
=108÷[35-[-1]
=108÷[35+1]
=108÷3
=3. Answer
Answered by
0
The value of the expression is 3
Step-by-step explanation:
Given:
expression = 108÷ [35-{48 ÷ 24 + (16-19)}]
To find:
simplify and find the value of the expression
Solution:
The expression will be solved using the BODMAS rule
When it comes to bracket we solve it in the order ( ), { }, [ }
Solving the smallest bracket ( )
108÷ [35-{48 ÷ 24 + (16-19)}]
= 108÷ [35-{48 ÷ 24 + (-3)}]
Now, solving the second bracket
= 108÷ [35-{48 ÷ 24 + (-3)}]
= 108÷ [35-{2 + (-3)}]
= 108÷ [35-{-1}]
Finally solving the square bracket [ ]
= 108÷ [35-{-1}]
= 108÷ 36
Dividing the numbers
= 3
∴ 108÷ [35-{48 ÷ 24 + (16-19)}] = 3
#SPJ2
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