Question

108 g mole
EXAMPLE 1.21 Calculate the number of atoms of oxygen present in 88 g of CO2. What would be the
mass of CO having the same number of oxygen atoms?
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Answer 1

Answer:

88gm CO2 i.e. 88÷2

=2 moles of CO2

2 mole CO2 contain 4 moles of oxygen

4 mole oxygen contain 4×6.022×10^23 atoms of oxygen

4 moles of CO has mass =4×28

=112g