Question

108a^2 - 3(b - c)^2 factorise pleaseeeeeeeeeeeeeeeeeee​

Answer 1

Answer:

3[(6a +b-c) (6a-b-c)]

Step-by-step explanation:

108a^2 -3(b-c)^2

take 3 common

3{36a^2- (b-c)^2}

now using the a^2 - b^2=(a+b)(a-b) identity

3[ (6a)^2 - (b-c)^2 ]

3{ (6a+b-c)(6a-b-c)}