10985 find the smallest number by which each of the following numbers must be divided to obtain a perfect cube
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Answer:
First prime factorise the number, e.g,
10985= 5 X 13 X 13 X13
Note: for a perfect cube the prime factors must be in the pair of 3 - 3
Now if any factor lacks in its pair of 3 e.g., here 5
Then multiply the whole number with the factor (by how much it lacks) e.g.,
Here the factor 5 lacks by 2
Since the smallest no. that must be multiplied to 10985 is 5X 5 = 25
Hope it's helpful for you
Have a great day ahead
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