Question

10a^2-5a(a+3)+4(2-3a) Please help step by step

Answer 1

$10a^2-5a(a+3)+4(2-3a)$

$= 10a^{2} - 5a^{2} - 15a + 8 - 12a$

$= (10-5)a^{2} + ( -15-12)a + 8$

$= 5a^{2} - 27a + 8$

Therefore.,

$\red{ 10a^2-5a(a+3)+4(2-3a) }$

$\green { = 5a^{2} - 27a + 8}$

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