10a(2p+q)^3-15b(2p+q)^2+35(2p+q).
pls factorise this
Answers
Answered by
4
I hope this is correct:
Assume (2p+q)=x
10ax³-15bx²+35x
=5x(2ax²-3bx+7)
Substituting x=(2p+q)
=5(2p+q)[2a(2p+q)²-3b(2p+q)+7]
=(10p+5q)[2a(4p²+q²+4pq)-6bp-3bq+7]
=(10p+5q)(8ap²+2aq²+8apq-6bp-3bq+7)
Assume (2p+q)=x
10ax³-15bx²+35x
=5x(2ax²-3bx+7)
Substituting x=(2p+q)
=5(2p+q)[2a(2p+q)²-3b(2p+q)+7]
=(10p+5q)[2a(4p²+q²+4pq)-6bp-3bq+7]
=(10p+5q)(8ap²+2aq²+8apq-6bp-3bq+7)
Similar questions