Math, asked by unzilanoor78, 3 months ago

10a-[4{5a-3(a-1)-3 (4a-3a+1)]​

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Answered by labdhee82
4

 \huge \mathbb \red{QUESTION}

10a-[4{5a-3(a-1)-3 (4a-3a+1)]

 \huge \mathbb \green{ANSWER}

10a-[4{5a-3(a-1)-3 (4a-3a+1)]

10a-5a+3a-4a+3a = 4+3+1+3-1

10a-2a-4a+3a = 7+1+3-1

10a-2a-1a = 8+3-1

8a-1a = 11-1

7a = 10

a = 10 x 7

a = 70

Answered by SIDDH2929
1

ANSWER

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