Question

10A current is passing through a very long wire radius 5 cm. Then magnetic fild at a distance of 2 cm inside from its curved surface ______×10^-5 T.

Answer 1

Answer:

9

Explanation:

i think it will helps you

Answer 2

Given:

10A current is passing through a very long wire radius of 5 cm.

To Find:

The magnetic field at a distance of 2 cm inside from its curved surface

Solution:

⇒ In this case, the magnetic field will be due to the current enclosed in amperian loop which will be Ie, not I.

⇒Now the current enclosed Ie​ is not I but is less than this value. Since the current distribution is uniform, the current enclosed is,

Ie = ​= I (πa²/πr²​) = i ( a²/r²​)

now use ampere law, according to which,

B ( 2πr ) = μ₀ i ( a²/r²​)

B =  μ₀ir/2πa²

put value in an expression,

B = ( 4π×10⁻⁷ × 10 × 5 )/ (2π × 4 )    where  μ₀=4π×10⁻⁷Wb/Am

B = 25 × 10⁻⁷

B = 2500 × 10⁻⁵

Hence the Magnetic field will be 2500 × 10⁻⁵ T.