Question

10a2 − 15b2 + 20c2 by factorization method

Answer 1

Answer:

We have, 10a

2

=2×5×a×a,

15b

2

=3×5×b×b

and,20c

2

=2×2×5×c×c

The three terms have 5 as a common factor

10a

2

−15b

2

+20c

2

=(2×5×a×a)−(3×5×b×b)+(2×2×5×c×c)

=5×(2×a×a−3×b×b+4×c×c)

=5(2a

2

−3b

2

+4c

2

)

Step-by-step explanation:

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