Question

10a²-15b²+20c² factorise ​

Answer 1

Answer:

Step-by-step explanation:

We have, 10a  

2

=2×5×a×a,

15b* 2  =3×5×b×b

and,20c* 2 =2×2×5×c×c

The three terms have 5 as a common factor

10a  2  −15b* 2  +20c* 2  =(2×5×a×a)−(3×5×b×b)+(2×2×5×c×c)  

=5×(2×a×a−3×b×b+4×c×c)

=5(2a  2  −3b  2  +4c  2 )