Question

10a2+17ab+6b2 factorise​

Answer 1

Answer:

$\Huge \boxed{20a+17ab+12b}$

Step-by-step explanation:

To solve this problem, first you have to use distributive property of $\displaystyle a(b+c)=ab+ac$. So remember to solve this problem, only need to do is identify variable of a and b.

Then, use operations of adding, subtracting, multiplication, and division.

First, multiply numbers from left to right.

$\displaystyle 10a*2+17ab+6b*2$

$\displaystyle 10*2=20$

$\displaystyle 20a+17ab+6*2b$

$\displaystyle 6*2=12$

$\bigstar\large\boxed{\textnormal{Therefore, the correct answer is \boxed{20a+17ab+12b}}}.\bigstar$

Answer 2

$\red {\huge {\underline{ \frak{Your \: answEr : }}}}$

$\purple{\huge{\boxed{ \tt \odot \: 20a + 17ab + 12b }}}$

$\red {\huge {\underline{ \frak{ Explanations : }}}}$

$\large{ \underline{\mathcal{ \star \: Given : }}}$

• Factorise 10.a.2 + 17.a.b + 6.b.2

$</p><p></p><p>\large{ \underline{\mathcal{\star \: Solution : }}}$

$\rightharpoonup \tt{(10 \times a \times 2 )+ (17 \times a \times b) + (6 \times b \times 2)}$

$\large{\blue{\boxed{ \rightharpoonup \tt{20a \: + \: 17ab \: + \: 12b}}}}$

$\huge{\red{\ddot{\smile}}}$