Question

10C charge is divided into two parts and kept at a distance 1m apart. What is the ratio of the two parts such that repulsive force between them is maximum?​

Answer 1

Answer:

Correct option is

D

2 : 1 : 1

q

1

+q

2

=Q

We know F=

r

2

kq

1

q

2

F=

r

2

k(q

1

)(Q−q

1

)

differentiate F w. r. t q

1

to find at what value of q

1

F is max

dq

1

dF

=

r

2

k

(Q−2q

1

)=0

q

1

=

2

Q

∴when q

1

=q

2

=

2

Q

force of repulsion is maximum

Q:q

1

:q

2

=Q:

2

Q

:

2

Q

=2:1:1