Question

10cm3 of cl2 gas at NTP has molecules?

Answer 1

Answer:

please mark me as brainliest

Explanation:

(0.010 L) / (24 L/mol) × (6.02 × 10^23 molecules/mol) = 2.5 × 10^20 molecules

Answer 2

Given:

Volume of Cl2 = 10 cm³

To Find:

The no of molecules in the given volume at NTP.

Calculation:

- We know that: 1 cm³ = 1 ml

⇒ Volume of Cl2 = 10 ml = 0.01 L

- At NTP, no of moles in 22.4 L of any gas = 1 mole

⇒ No of moles in 0.01 L of Cl2 = (1/22.4) × 0.01

⇒ No of molecules = (0.01/22.4) × 6.022 × 10²³

⇒ n = 2.6884 × 10²⁰

- So, 10cm3 of Cl2 gas at NTP has 2.6884 × 10²⁰ molecules.