Math, asked by vaibhav6352, 1 year ago

10cos30°-15cos75°-16cos45​°​

Answers

Answered by saiagarwal707
0

10cos30°-15cos75°-16cos45°

=(10×0.15)-(15×0.92)-(16×0.52)

=1.5-13.8-8.32

=-20.62

Similar questions