Question

10g limestone produces 1.8 litre co2 at stp what is percentage purity of limestone?​

Answer 1

Answer:

Answer :- 75 %

SOLUTION:-

10g of limestone i.e. CaCO3​ contains= 100g/mole10g​ moles of CaCO3​=0.1 moles of CaCO3​

CaCO3​⟶CaO+CO2​

1 mole of CaCO3​ produce 1 mole of CaO

Thus 0.1 moles of CaCO3​ must produce 0.1 mole of CaO

10g of CaCO3​ must produce 0.1×56=5.6g of CaO

But CaO produce is 4.2g

Pure product obtained is 4.2g from 10g of CaCO3​

Product that obtain along with 1 m purity from 10g of CaCO3​ is 5.6g

So, percentage purity= mass of impure substance obtainedmass of pure substance obtained​×100

% purity= 5.64.2​×100=75%