Question

10g moving body is acted upon by a force of 10N for 3micro second. compute the impulse and the change in velocity of the body​

Answer 1

Answer:

Impulse = 3.33×10^6 N s

(or 3.33 mega newton second)

Change in velocity (acceleration = 1000 m/s²

Explanation:

Impulse = force/time

Change in velocity (acceleration) = force/mass

Answer 2

Explanation:

Given that,

Mass of body, m = 10 g = 0.01 kg

Force acting on the body, F = 10 N

Time, $t=3\ \mu s=3\times 10^{-6}\ s$

Impulse of a body is given by the product of force and time. It is given by :

J = F × t

$J=10\times 3\times 10^{-6}$

$J=30\times 10^{-6}\ N-s$

Also, the change in momentum is equal to the Impulse.

J = m(v-u)

$(v-u)=\dfrac{J}{m}$

$(v-u)=\dfrac{30\times 10^{-6}}{0.01}$

(v-u) = 0.03 m/s

Hence, this is the required solution.