Question

10g of a gas at 1 atm and 273k occupies 5 litres. the temperature at which the volume becomes double for the same mass of gas at the same pressure is.? answers

Answer 1

Using Charles law, new temperature is 273*2=546 K

Answer 2

Answer: The temperature at which the volume becomes double for the same mass of gas at the same pressure is 546 Kelvins.

Explanation:

Given:

$\text{Pressure of the gas}= 1 atm, T_1=273 Kelvins,V_1=5 L$

$V_2=2V_1= 2\times 5=10 L,T_2=?$

According to Charles law:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Substituting values in above equation:

$\frac{5 L}{273 K}=\frac{10 L}{T_1}$

$T_1=\frac{10 L}{5 L}\times 273 K=546 K$

The temperature at which the volume becomes double for the same mass of gas at the same pressure is 546 Kelvins.