Question

10g of a gas at 1atm, 273k occupies 5 litres. The temperature at which the volume becomes double for the mass of gas at the same pressure is

Answer 1

Answer. The new temperature will be 546 K.

Explanation :

Given :

$V_1=5L,P_1=1atm,T_1=273K$

Weight of gas = 10g

$V_2=10L ,P_2 =1(constant),T_2=?K$

According to question pressure is constant, so we will apply Charles' law:

Charles' Law: The volume of gas is directly proportional to temperature of the gas ,when pressure is held constant.

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{5}{273}=\frac{10}{T_2}$

$T_2=\frac{10}{1}\times \frac{273}{5}$

$T_2=546K$

Answer 2

Explanation:

V1 =5l

P1 =1atm

Weight of gas =10g

V2 =10l