10g of calcium carbonate was produced when carbon dioxide was added to lime water
(calcium hydroxide in solution). What volume of carbon dioxide at STP was needed?
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Explanation:
.no. of moles = mass/molar mass
=10/100
=0.1
CaCO3=CaO+CO2
so for CO2
volume = no. of moles×22.4
=0.1×22.4
=2.24 L
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