10g of glucose (molar mass= 180) is dissolved in water. The mass of solution is 1000g (density of solution is 1.2g/ml) Calculate its (0) Molarity (i) Molality.
Answers
Answer:
14.5g of NaCl is equal to 0.248 mol according to the equation
n=mM
Now, this equates to 1.495×1023 Sodium chloride molecules.
We get this if we multiply 0.248 mol with Avogadro's number, 6.022×1023
Each molecule of Sodium chroride holds two atomic ions bonded in an ionic bond- Na+ and Cl− in a 1:1 ratio. This means that the amount of molecules correspond with each of the individual ions.
So :
Number of Sodium ions=Number of Chloride ions= 1.495×1023 ions
So the total amount of ions is twice this number, 2.990×1023 ions in total.
Answer:
Explanation:
No. Of Moles of Glucose = 10/180 = 18mol
Volume of solutions = mass /density
= 1000/1.2 ml = 1/1.2 litre
So,
Molarity = moles / volume (in litre)
=(1/18)/(1/1.2)
= 1.2/18 = 1/15 M or 0.067M
For molality
Mass of solvent = 1000-10 = 990gm = 0.99kg
molality = moles / mass of solvent in (kg)
= (1/18) / 0.99 = 0.056m