Question

10g of hydrogen and 46g of nitrogen are mixed in a container of volume one litre calculate mole fraction of hydrogen

Answer 1

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Answer 2

Mole fraction of hydrogen is 0.75

Explanation:

10 g of hydrogen and 46 g of nitrogen

moles of hydrogen = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{10g}{2g/mol}=5moles$

moles of nitrogen = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{46g}{28g/mol}=1.64moles$

Total moles = moles of hydrogen + moles of nitrogen = 5 + 1.64 =6.64

Mole fraction of a substance is given by:

${\text {mole fraction of hydrogen}}=\frac{\text {moles of hydrogen}}{\text {Total moles}}=\frac{5}{6.64}=0.75$

${\text {mole fraction of nitrogen}}=\frac{\text {moles of nitrogen}}{\text {Total moles}}=\frac{1.64}{6.64}=0.25$

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