10g of hydrogen and 64 g oxygen were filled in a steel vessel and exploded.amount of water produced in this reaction will be?
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10g H2 = 10/2= 5 moles
64g O2 = 64/32 = 2 moles
H2 + 1/2 O2 = H2O
Therefore no of moles of H2 must be double than no of moles of O2
Hence 4 moles H2O produced
W = 4 x 18 = 72 g H20 produced.
64g O2 = 64/32 = 2 moles
H2 + 1/2 O2 = H2O
Therefore no of moles of H2 must be double than no of moles of O2
Hence 4 moles H2O produced
W = 4 x 18 = 72 g H20 produced.
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