10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded volume of gaseous
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Explanation:
Mass of hydrogen=10g
No. of moles of hydrogen=w/M
=10/2 mol =5mol
Mass of oxygen=64g
No. of moles of oxygen=w/M
=64/38 mol =2mol
According to the reaction,
2H2+O2= 2H2O
Hence, for 2moles of oxygen, 4moles of hydrogen are required and 4moles of water is produced. Here oxygen is the limiting reagent.
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