Question

10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be?​

Answer 1

Answer:

Mass of hydrogen =10g

No. of moles of hydrogen =w/M= 10g/2gmol-1 =5mol

Mass of oxygen =64g

Moles of oxygen = w/M = 64g /32gmol-1 = 2mol

According to the reaction, 2H2 + O2 ------------ 2 H2O

Hence, for 2 moles of oxygen, 4 moles of hydrogen are required and 4 moles of water is produced. Here oxygen is the limiting reagent

Answer 2

Given :-

H2 = 10g ; O2 = 64g

To find :- amount of H2O produced in this rxn.

The equation goes like

2H2 + O2 ➡ 2H2O

Now;

no of moles of H2 = 10/3

= 5 moles

no of moles of O2 = 64/32

= 2 moles

This implies that 2 moles of O2 will give 4 moles of H2O.

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