10g of hydrogen reacts with 26g of oxygen. Calculate the amount of product formed.
Answers
Answer:
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations10 g of hydrogen and 64 g o...
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations10 g of hydrogen and 64 g o...CHEMISTRY
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations10 g of hydrogen and 64 g o...CHEMISTRY10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations10 g of hydrogen and 64 g o...CHEMISTRY10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:HARD
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations10 g of hydrogen and 64 g o...CHEMISTRY10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:HARDHelp best friend
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations10 g of hydrogen and 64 g o...CHEMISTRY10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:HARDHelp best friendStudy later
Some Basic Concepts of ChemistryStoichiometry and Stoichiometric Calculations10 g of hydrogen and 64 g o...CHEMISTRY10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:HARDHelp best friendStudy laterVIDEO EXPLANATION
10 g of hydrogen (molar mass 2 g/mol) =
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) =
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.
10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of oxygen (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.Here, oxygen is the limiting reagent and hydrogen is the excess reagent.