Question

10g of ice at 0 degree Celsius is mixed with10 GM of water at 30 degrees Celsius . Find the temperature of mixture in equabrilium

Answer 1

Given:

10 g of ice at zero degree celsius have been mixed with 10 g of water at 30° C.

To find:

Temperature of mixture in equilibrium.

Calculation:

This is question of calorimetry;

Let the temperature of mixture be $\theta$.

Melting of ice at 0°C will take :

$\sf{heat = mass \times latent \: heat}$

$\sf{ = > heat =10\times 80}$

$\sf{ = > heat =800 \: calories}$

The maximum amount of heat that can be provided by water at 30° C:

$\sf{heat = m \times c \times \Delta \theta}$

$\sf{ = > heat = 10 \times 1 \times (30 - 0)}$

$\sf{ = > heat = 300 \: calories}$

Since main amount of heat provided by water at 30°C is lesser than that required by ice at 0°C ,some of the ice will not get melted and hence the temperature of mixture will be 0°C.

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