Question

10g of ice at 0 o c absorbs 5460 J of heat energy to melt and change to water at 50 o c calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J kg -1 o c -1 .

Answer 1

Total heat = Latent Heat of Fusion + Heat to change the temp from 0°C to 50°C

⇒5460 = 0.01×L + 0.01×4200×50
⇒0.01L = 5460 -2100
⇒0.01L = 3360
⇒L = 336000 = 336 kJ

Answer 2

it is attached below