10g of ice at -10°C is added to 10 g of water at 85°C. What is the final temperature and amount of ice left in the system?
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Explanation:
hot body lost=cold body gain
let the final temperature=T
- heat lost by hot body=msΔT
- and that is equal to 10g
- specific heat of ice=0.5
∴Q=(10)×(0.5)×(T-(-283K)⇒[2]
- mass of water=10g
- specific heat of water=1
- tempature of water=85°C
∴Q=10×1×(358-T)⇒[1]
EQUATING BOTH [1],[2] we get the value of T as≅144
complete ice will be dissolved
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