10g of ice at-10C is added to10g of water at 85C.what is the final temperature and amount of icr left in the system? Pizzas answer quickly
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specific heat of ice = 0.5 cal/gm/^oC
10 gm ice at -10 will need
10 x 10 x 0.5 = 50 calories of heat for rising to ice at 0^oC
10 gm ice at 0 will need
10 x 80 = 800 calories of heat in converting to 10 gm water at 0
so, the total heat consumed so far = 850 calories
10 gm water at 85 can give
10 x 1 x 85 = 850 calories of heat in coming to 10 gm water at 0
this is exactly equal to the 850 calories calculated above
therefore, the resultant will be 20 gm water at 0 with no unmelted ice left
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