Question

10g of ice at-10C is added to10g of water at 85C.what is the final temperature and amount of icr left in the system? Pizzas answer quickly

Answer 1

Answer:

specific heat of ice = 0.5 cal/gm/^oC

10 gm ice at -10 will need

10 x 10 x 0.5 = 50 calories of heat for rising to ice at 0^oC

10 gm ice at 0 will need

10 x 80 = 800 calories of heat in converting to 10 gm water at 0

so, the total heat consumed so far = 850 calories

10 gm water at 85 can give

10 x 1 x 85 = 850 calories of heat in coming to 10 gm water at 0

this is exactly equal to the 850 calories calculated above

therefore, the resultant will be 20 gm water at 0 with no unmelted ice left