10g of MnO2 on reaction with hcl forms 2.24L of Cl2(g) at NTP, the percentage impurity of MnCl2 is:
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according to the equation 1 mole of Cl2 is formed ffrom 1 mole of MnO2
ie 22.4 L of Cl2 is formed from 87 g of MnO2
hence 2.24 L will be formed from 8.7 g of MnO2
hence impurity in MnO2 is = 10 - 8.7 g = 1.3 g
hence % impurity = 1.3 / 10 x 100 = 13%
note : in the question it is given the % impurity of manganese chloride which is not correct because it is 10 g of MnO2 not MnCl2 .
ie 22.4 L of Cl2 is formed from 87 g of MnO2
hence 2.24 L will be formed from 8.7 g of MnO2
hence impurity in MnO2 is = 10 - 8.7 g = 1.3 g
hence % impurity = 1.3 / 10 x 100 = 13%
note : in the question it is given the % impurity of manganese chloride which is not correct because it is 10 g of MnO2 not MnCl2 .
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