Question

10g of Na was made to react with 8g of H2O to form hydrogen gas. Identify the limiting reagent and calculate the mass of hydrogen formed.

Answer 1

Answer:

9 gm

Explanation:

The molecular masses of hydrogen, oxygen and water are 2 g/mole, 32 g/mole and 18 g/mole respectively.

2H

2

+O

2

→2H

2

O

2×2=4 g of hydrogen reacts with 1×32=32 g of oxygen to form 2×18=36 g of water.

Hence,

4

4

=1 g of hydrogen reacts with

4

32

=8 g of oxygen to form

4

36

=9 g of water.

9 grams of water can be produced when 8 g of hydrogen reacts with 8 g oxygen.