10g of Na was made to react with 8g of H2O to form hydrogen gas. Identify the limiting reagent and calculate the mass of hydrogen formed.
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Answer:
9 gm
Explanation:
The molecular masses of hydrogen, oxygen and water are 2 g/mole, 32 g/mole and 18 g/mole respectively.
2H
2
+O
2
→2H
2
O
2×2=4 g of hydrogen reacts with 1×32=32 g of oxygen to form 2×18=36 g of water.
Hence,
4
4
=1 g of hydrogen reacts with
4
32
=8 g of oxygen to form
4
36
=9 g of water.
9 grams of water can be produced when 8 g of hydrogen reacts with 8 g oxygen.
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