Question

10g of piece of marble was put into excess of dilute HC Tacid. When reaction was complete 1120 cm3 of coz was obtained at STP, evaluate the value of x 710 where x = % of CaCO3 in marble .

ans fast Please argent​

Answer 1

CaCO

3

+2HCl→CaCl

2

+H

2

O+CO

2

100g or one mole 24000ml

100 g of CaCO

3

gives 22400 ml of carbon dioxide.

10 g of CaCO

3

gives =

100

22400

×10=2240 ml of carbon dioxide.

If the metal is 100% pure, 2240 ml of carbon dioxide is produced.

1120 ml of carbon dioxide is produced in this case.

So the % purity =

2240

100

×1120=50%

Answer 2

Answer:

here is your ans

Explanation:

F.O.L.L.O.W. M.E